Answer by Jerrold Franklin for $\mathbf F'=\mathbf F$ in special relativity
The covariant Minkowski force can be written in terms of the three-vector force as\begin{equation}{\cal F}^\mu=\left[\gamma\frac{dW}{dt},\gamma{\bf F}\right],\end{equation}where $\bf F$ is three-vector...
View Article$\mathbf F'=\mathbf F$ in special relativity
Assume that an inertial observer $S'$ is moving with a velocity $\mathbf u$ relative to another inertial observer $S$ along the $x-$axis.Now, imagine that the two observers observe a force being...
View Article
More Pages to Explore .....
